Suppose we have this setup: There are four objects: A, B, C, D. Each object is painted either Red or Blue.
Now we have the following condition: There are 2 Red objects that are not A.
Does this mean that there are EXACTLY 2 Red objects, and so that A and another unknown object are Blue. Or do we only know that there are at LEAST 2 Red objects and we do not know anything about the color of the other two (which includes A)?
I don't think I've seen any official LSAT question with a wording like this. However, I saw a game in a prep-book (author's own creation) where the correct answer used the first interpretation. This caught me off guard since I had the second interpretation in mind.