Q9

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ManhattanPrepLSAT1
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Q9

by ManhattanPrepLSAT1 Mon Oct 07, 2013 2:13 pm

9. (E)
Question Type: Conditional

Tough question! This question gives us multiple pieces of extra, conditional ("If") information that will apply to this question only: G is shown three times, H twice, and L once. Given these conditions, we’re looking for the answer that "must be true" in all cases.
The first thing we want to do is use our diagram and the additional information to create inferences.
First, if G is shown on all three days, then H can’t be shown on Saturday (remember, either G or H, but not both, is shown on Saturday).
Next, if H is shown twice, and if H is NOT shown on Saturday, then H must be shown on Thursday and Friday. Remember that G is shown on all three days, so Friday must have H first and G second.
If we do a good job of following the inference chain, we’ll often be led directly to the correct answer. Knowing that H and G are both shown on Friday seems like a big inference. Let’s check the answers to see if one matches. Sure enough, (E)’s the one. On conditional questions, follow the inference chain before you start a trial and error approach! You’ll most definitely save yourself a lot of time.

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MatthewW59
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Re: Q9

by MatthewW59 Sun Feb 18, 2018 10:54 pm

If the analysis shows that two films were shown on saturday, then why would B be incorrect?
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ohthatpatrick
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Re: Q9

by ohthatpatrick Tue Feb 20, 2018 2:35 pm

The diagram doesn't show two films on Saturday for sure.

It's showing that G is definitely on Saturday, and L might be.

The "L / " and " / L" is a notation we use to show either or. So if you look at Thu and Sat, you see an "L / " and a "/ L", indicating that L is either on Thursday or Saturday.

Since (B) doesn't HAVE to be true (i.e. L could be on Thursday, and only G would be on Saturday), it's incorrect.

Hope that helps.