My reasoning process:
Conlusion: bear population in V will increase if the conditions remain the same.
In eight years, bear population in P increased (nearly doubled).
↓
How can population increase happen? → Only two ways: birth; migration.
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How can migration happen? → Only two ways: from places (outside P and) outside V; from places (outside P and) inside V
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So we can only get the population increase from: (N1) birth (inside P); (N2) migration from (outside P and) outside V; and/or (N3) migration from places (outside P and) inside V
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If in eight years we do not have N3 → with only N1 and/or N2, when all other conditions remain unchanged → cannot weaken
So to weaken the argument, we must have N3.
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We need the mere existence of N3, or how much N3 is also matters?
If in eight years we only have one bear of N3 → all remaining increase came from N1 and/or N2, when all other conditions remain unchanged → cannot weaken
So how much N3 is does matter.
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Thus, the more we can discriminate N3 from N1 and/or N2, the better an answer choice is.
(Sure, an ideal answer would be something like “N3 exists and is sufficiently large that we can ignore N1 and/or N2”)
A : the discrimination can be inferred here is N1 vs. N2+N3, but we need N3 rather than N1 to stands out → eliminate
B : yes N3 stands out here, but “only some” looks confusing → defer
C : like A, the discrimination can be inferred here is N1 vs. N2+N3 → eliminate
D : like A, the discrimination (if any) can be inferred here is N1 vs. N2+N3 → eliminate
E: the discrimination can be inferred here is N3 vs. N1 → defer
Now take a closer look at B and E:
Assume that in eight year there is no death / migration out of V, (we can go on without this assumption but it makes things easier since we can supply zero)
Information in B: N3 exists, N2 exists, N1 unknown
Information in E: N3 exists, N2 about zero, N1 about zero
N3 is good, N1/N2 is baaaaaaaad, so E is better.