by timmydoeslsat Fri Sep 28, 2012 10:20 pm
A, C, and E can certainly be true, but they do not have to be true like B must be.
x: _ K P _ ...J
y: _ L _ _ ...MN
This is the information we can plug into our diagram. If you did not know that MN must be on Y and J must be on X, please tell me, as it is the must have inference in the game.
So, looking at this setup can yield the inference that R is going to be in slot 1, but whether it is X1 or Y1 is up for debate.
For extra practice, you could pretend that this was a could be true question, or a question wanting a different answer. You could frame this with R going into X1 and then R going into Y1.
X1 frame:
x: R K P _ ...J
y: _ L _ _ ...MN
You know J must now be in X4...
x: R K P J
y: _ L _ O ...MN
You know that O must now be in Y4 since O must be in a four.
x: R K P J
y: _ L _ O ...MN
You know that N must be in Y3 since we have a not rule with M. Which means that M must be in Y1.
x: R K P J
y: M L N O
Y1 frame:
x: _ K P _ ...J
y: R L _ _ ...MN
You know that with the M not rule in Y3, that N must got there and M goes into Y4, which then forces O into X4. Which then forces J into the one and only slot left in X, X1.
x: J K P O
y: R L N M