Q23

[andreperez7]

Answer choice A

Let’s follow the cascade of inferences and scenarios that occur if you put L in 7 and O in 8.

1) L must go into 2(Rule# 2)

2) We look as to where our HM chunk (Rule#4) can go, and we think can possibly go into 3, 4, and 5. However, if H goes into 5, then it goes into 1, which is invalid, because of rule #5. (Remember, Q19 brought this to our attention.) So HM can only go into 3 or 4.

3) We end up with two frames:

Frame 1: HM in 3, leads to J in 1 (Rule#5), which leads to J in 5 (Rule#1), leaving G in the only available space, space 6.

Frame 2: HM in 4 leads to M in 1(Rule#1), which leads to J in 3 (Rule #5), leaving G in the only available space, space 6.

5) We see that in

Frames:

__1_2_3_4_5_6_7_8
1_J_L_H_M_J_G_L_O
2_M_L_J_H_M_G_L_O