The diagram gets its own thread, so if you back out to the beginning of this Game in the forum hierarchy, you can read about how people set it up:
https://www.manhattanprep.com/lsat/foru ... -t397.htmlIf J doesn't review T, then he reviews S or U.
In this game, we know that M reviews 2, J reviews 1, K reviews 1, L reviews 1, and O reviews 1, 2, or 3.
J and M can't have any in common, so we either have
J = S
M = T, U
or
J = U
M = T, S
The common denominator of those two scenarios is that no matter what, M reviews T.
That's why (D) is our correct answer.
(A) flexible: J could do S or U
(B) flexible: when J does S, L could do T or U
(C) flexible: M might be doing T and U only
(D) mandatory
(E) flexible: O might only review T