by maryadkins Thu Jun 19, 2014 4:30 pm
You're close! But think about what happens if X goes in in the 2nd bite with U and Y: there are no letters left for the 3rd bite, and we have to have at least 1 letter in each bite:
1: W T Z
2: U Y X
3: ???
So either U and Y are in 2, and X is in 3, or U, Y and X are all in 3.
Hope this helps.