Q17

[mitrakhanom1]

can somebody please explain why the answer is B and not A? How did you figure out its B? using my diagram S has J, F, and O/R. T has O and R. V has F and an open space. X has all four. Z has either O or R and an open space. For answer choice A its possible if S has O and since T has O that it could be true. It could be S has R instead of O making it possibly false. Answer choice B i'm having trouble with since V has F already and it has either O or R but if it has O then Z has r and vice versa since V and Z cannot have the same thing. So since this also could be true and could be potentially be false how is this a better answer choice than A?

[rinagoldfield]

Thanks for your question! Great job making your new diagram--I agree with how you placed your elements.

However, (A) must be false. I agree that S has F, J, and O/R. But T has both O AND R. So if S has O, S will overlap with T’s O. If S has R, S will overlap with T’s R. There will always be a point of overlap.

(B) could be true or false. S and Z could have zero points of overlap; for example, S could have R, F, and J and Z could have only O.

Your right answer on a "Could Be True" question always "could be potentially be false;" anything that "could be true" could also be false. That’s the definition of "could be." The wrong answer choices on such a question "must be false"--which (A) is in this case.

Hope that helps.

[IsaacS381]

How is E wrong? I have the diagram written out like this:

S-FJR
T-RO
V-RO
X-JFRO
Z-F

This satisfies all the rules:
1. Only two stores carry J
2. T has R & O and no others
3. S has more than T (so, 3)
4. X has more than any other store (so, 4)
5. One of the types S carries is J
6. V doesn't have any that Z has

How is "T & V carry 2 types in common" wrong? What am I missing? (I'm sure it'll be obvious once someone points it out…)