by ohthatpatrick Wed Jan 23, 2019 2:36 pm
We know that T is 1, but T is a floater so that doesn't immediately tell us anything:
T __ __ __ __ __
So, whenever we have a chunk, we use the chunk as our starting point for limiting possibilities. Where could the chunk go? 2/3, 3/4, 4/5, 5/6?
We know it can't go 3/4, because we have to save one of those spots for S.
But the other three options seem possible.
T W Z __ __ __
T __ __ W Z __
T __ __ __ W Z
In the first two worlds, we know where S would have to go, because only one of its two eligible spots is left.
T W Z S __ __
T __ S W Z __
T __ __ __ W Z
We have to make sure that R and V don't touch, so the first world is broken. It would force R and V into the final two spots. So we're down to only these two worlds:
T __ S W Z __
T __ __ __ W Z
In the first world, we split up R and V on spots 2 and 6.
In the second world, we split up R and V on spots 2 and 4. (that leaves S in 3)
T r/v S W Z v/r
T r/v S v/r W Z
Since we're doing a must be true (and we had more than one world) we can try to anticipate the answer by looking for anything that is ALWAYS true, i.e. true in both worlds.
The only constant here is that S is 3rd, so we'd look for that answer.
(C) is correct.
(A) 2nd could be R or V
(B) 4th could be W, V, or R
(D) W could be 4th or 5th.
(E) Z could be 5th or 6th.