Q11

[rsmorale]

Hi, I am having trouble with Q11. I chose D. Can someone kindly walk me through why A is the correct answer? What inferences/rules did I need to consider in order to know this answer?

[peg_city]

Hi, I am having trouble with Q11. I chose D. Can someone kindly walk me through why A is the correct answer? What inferences/rules did I need to consider in order to know this answer?

A is correct because Gwen is from Seattle. Because there are two people each from Vancouver and Seattle and because F can't be from Seattle then that leaves G.

I/M I/M H G/F G/F

M(~) + F(~) = Seattle, and two people need to be from Seattle. So that leaves Gwen and Isaac to be from Seattle and Live (3rd inference)

[ManhattanPrepLSAT1]

Nice work peg_city!

So that leaves Gwen and Isaac to be from Seattle and Live (3rd inference)

I'm sure it was clear to most everyone, but it's the 3rd "constraint" that peg_city was referring to. An "inference" would be something we arrived at, whereas it's the 3rd constraint that supports the inference that Gwen and Isaac's calls are Live.

[pkarguello]

Nice work peg_city!

So that leaves Gwen and Isaac to be from Seattle and Live (3rd inference)

I'm sure it was clear to most everyone, but it's the 3rd "constraint" that peg_city was referring to. An "inference" would be something we arrived at, whereas it's the 3rd constraint that supports the inference that Gwen and Isaac's calls are Live.

So are you saying that if faced with two answer choices that are right based on our diagramm we should go with the one that is an actual "constraint" and not an "inference"?

Thanks! I appreciate your insights on this!

[timmydoeslsat]

Nice work peg_city!

So that leaves Gwen and Isaac to be from Seattle and Live (3rd inference)

I'm sure it was clear to most everyone, but it's the 3rd "constraint" that peg_city was referring to. An "inference" would be something we arrived at, whereas it's the 3rd constraint that supports the inference that Gwen and Isaac's calls are Live.

So are you saying that if faced with two answer choices that are right based on our diagramm we should go with the one that is an actual "constraint" and not an "inference"?

Thanks! I appreciate your insights on this!

If faced with the situation of my diagram containing two "right" answers on a problem, then I would redo my diagram. You would not even be sure that the correct answer is one of the two. There is an inconsistency somewhere in the diagram.

Did you run into this problem on this game?

[ManhattanPrepLSAT1]

So are you saying that if faced with two answer choices that are right based on our diagramm we should go with the one that is an actual "constraint" and not an "inference"?

Thanks! I appreciate your insights on this!

Thanks Timmy! I agree. If I ran into two answer choices that both appeared as if they must be true. I would rework my setup; something is off.

I/M M/I H F/G G/F
1 -----------> 5
If neither M nor F are from Seattle, then I and G must be from Seattle. M and F will be from Vancouver. Both the Seattle calls are live. So we know that I and G are from Seattle, and that they're live. That doesn't tell us whether M or F is live or taped though.

Let's look at the incorrect answer choices:

(B) must be false, since H, which is 3rd, is from Kelowna and is taped.
(C) could be false, since we do not know whether M is live or taped.
(D) could be false, since we do not know whether M is live or taped.
(E) must be false, since I must be live.