by Laura Damone Wed May 05, 2021 7:02 pm
Any time you only have 2 elements (which is common in the top row of a 3D ordering game!), try asking yourself about the two most extreme scenarios for those elements:
1. Can they just alternate?
2. Can all the M's be on one side of the diagram and all the S's on the other?
Playing out those two scenarios in your head will frequently lead you to the inferences about the kind of alternation that is required, prohibited, and allowable. For example, if the elements can't just alternate, they have to chunk up, at least some times. For this game, that let's me realize that I can't have M's between all my S's, so the S's have to chunk up at least once. Same for the M's: they can't all have S's between them so they have to chunk up. Now that I have an MM chunk, an SS chunk, an extra M, and two extra S's, the game is a lot more limited. Whenever you have a chunk, think about the places it could go. The MM chunk will either include the M already in the board, attach to that M, or be separated from that M by an S. This kind of spatial reasoning is really important for efficiency. I'm not drawing out every possibility, but I'm looking at it spatially thinking "where is there room for this" and "what does that mean for the cleanings"
Additionally, or even alternatively, you can look at the "all the M's on one side, all the S's on the other side" option. Doing so will show you that this is the only way 1 cleaning can play out. The logical next step is to think about 2 cleanings. If you have 2 cleanings, you're gonna have all of one set of elements sandwiched on either side by the other elements. This only works if the M's are sandwiched because of M's existing placement. Just wrapping your head around that can help you enter the questions confident and ready to play!
Laura Damone
LSAT Content & Curriculum Lead | Manhattan Prep