JianiL759
Thanks Received: 0
Vinny Gambini
Vinny Gambini
 
Posts: 4
Joined: March 15th, 2020
 
 
 

Re: Logic Game Challenge #34: Party Problem (Hard)

by JianiL759 Tue Mar 17, 2020 3:54 am

Could anyone please help with me with Q6? Answers B and C both contain Lance, but if all four women come to the party how can Lance be present considering that if both he and Reena come Tracy won't come?
 
Laura Damone
Thanks Received: 94
Atticus Finch
Atticus Finch
 
Posts: 468
Joined: February 17th, 2011
 
 
 

Re: Logic Game Challenge #34: Party Problem (Hard)

by Laura Damone Thu Mar 26, 2020 2:54 pm

First, sorry for the delayed response here. Amidst all the chaos of the last week, this one slipped through the cracks.

Second, it looks like you accidentally reversed the Lance Tracey Reena rule. The rule tells us that Tracey is coming unless both Lance and Reena come. The best way to diagram a compound "unless" statement (as in, an "unless" statement with an "and" or an "or"), is to think about drawing the arrow through the word "unless." The word "unless" will introduce the necessary condition(s). The other part of the statement, negated, becomes the sufficient condition.

That give us this:

- Tracey --> Lance and Reena

And the contrapositive:

- Lance or - Reena --> Tracey

Notice we had to change the "and" to "or" when we contraposed. You will always do this when you contrapose a compound conditional statement.

With the rule properly diagrammed, you can see that Lance and Reena don't force Tracey out.

The reason that C is impossible and therefore correct is that it contains both Lance and Oscar. Rule # 2 tells us that if Oscar and Pam come, Lance won't:

Oscar + Pam --> - Lance

And the Contrapositive:

Lance --> - Oscar or - Pam

Again, notice that we switched the "and" to "or" when we contraposed.

So, if all four women are at the party, Pam is in for sure. That means if Oscar is in, it triggers the rule and kicks Lance out. If Lance is in, it triggers the contrapositive, and since Pam can't get kicked out, Oscar gets the boot. You can't have Oscar and Lance together at any party Pam attends.

Hope this helps!
Laura Damone
LSAT Content & Curriculum Lead | Manhattan Prep
 
JianiL759
Thanks Received: 0
Vinny Gambini
Vinny Gambini
 
Posts: 4
Joined: March 15th, 2020
 
 
 

Re: Logic Game Challenge #34: Party Problem (Hard)

by JianiL759 Wed Jun 03, 2020 9:55 am

Laura Damone Wrote:First, sorry for the delayed response here. Amidst all the chaos of the last week, this one slipped through the cracks.

Second, it looks like you accidentally reversed the Lance Tracey Reena rule. The rule tells us that Tracey is coming unless both Lance and Reena come. The best way to diagram a compound "unless" statement (as in, an "unless" statement with an "and" or an "or"), is to think about drawing the arrow through the word "unless." The word "unless" will introduce the necessary condition(s). The other part of the statement, negated, becomes the sufficient condition.

That give us this:

- Tracey --> Lance and Reena

And the contrapositive:

- Lance or - Reena --> Tracey

Notice we had to change the "and" to "or" when we contraposed. You will always do this when you contrapose a compound conditional statement.

With the rule properly diagrammed, you can see that Lance and Reena don't force Tracey out.

The reason that C is impossible and therefore correct is that it contains both Lance and Oscar. Rule # 2 tells us that if Oscar and Pam come, Lance won't:

Oscar + Pam --> - Lance

And the Contrapositive:

Lance --> - Oscar or - Pam

Again, notice that we switched the "and" to "or" when we contraposed.

So, if all four women are at the party, Pam is in for sure. That means if Oscar is in, it triggers the rule and kicks Lance out. If Lance is in, it triggers the contrapositive, and since Pam can't get kicked out, Oscar gets the boot. You can't have Oscar and Lance together at any party Pam attends.

Hope this helps!


Oh I see. Thank you so much!