I really think 6 does not have a correct answer, and I explain why below in more detail, as part of my solutions. I believe I've found counterexamples all the choices (as well as general rules explaining the counterexamples). For A, B, C, and D, I have sequences which are allowed by the original rule but not by the new rule, and for E I have a sequence that's allowed by the new rule and not by the original rule. I've checked them all backward and forward against the game rules and I can't find anything wrong with any of them, however Noah claims that I've missed something and that there is indeed a correct answer. Can somebody find the flaw in my reasoning?
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In any case, here are my solutions:
We have eight elements: Fi, Gi, Hi, Km, Lm, Pw, Ow, and Sw. The first (capital) letter in each of these symbols is the specific name of the element, the second (lower-case) letter is its type.
We have 6 or 7 layers, which means either 2 elements or 1 element will be left out, respectively.
There must be at least one element of each type selected, so if we have 6 layers we cannot leave out both m's.
We have the following rules:
I. The sequence ii (insulator followed by insulator) is forbidden.
II. An i may not be first or last.
III. The sequences FL (fleece followed by lead) and LF (lead followed by fleece) are forbidden.
IV. The sequences KF or FK may occur only as iKF or FKi.
V. The sequences mw and wm are forbidden.
VI. Wood must be both first and last or neither first nor last.
We can also make the following deductions:
1. Combining II and VI tells us that the first and last elements must either be both w or both m.
2. Combining VII and V tells us that we have the following possible block arrangements, where slots in parentheses are present in the 7-element case:
(a) mi_(_)_im
(b) wi_(_)_iw
(c) wwi_(_)iw, wi_(_)iww
Examining these block arrangments in the light of I, V, and the fact that there are only two m's gives the following possibilities:
(a) miwwim, miwiwim, miwwwim
(b) wimmiw, wimimiw, wimiwiw, wiwimiw
(c) wwimiw, wwimmiw, wimiww, wimmiww
Since F is so restricted, it's worth noting that we can also make one more deduction about these sequences:
3. The sequences miwwim, miwwwim, wimmiw, wwimmiw, and wimmiww may not include F, as rules III and IV tell us that F (an i) may only be next to either w or an m which has an i on the other side, and this is not possible in these sequences.
Now for the actual problems:
1. (E)
This is a simple exercise in checking the rules against the answer choices. My preferred method of attack is to pick the rule that seems easiest to check, apply it to all the choices, eliminate those that fail, select the next-easiest rule, and repeat until all but one choice has been eliminated.
II and VI simply require examination of the first and last elements rather than a search through each entire list, so they're good starting points. II doesn't help, but VI allows us to eliminate (B).
III is very simple and specific and so is a good next choice. It eliminates (A).
IV is nearly as specific, so it's next. It eliminates (D).
I and V are next, and V eliminates (C).
(E) is therefore the answer.
2. (C)
If F is second, the allowed sequences are those with an insulator second, which includes all type (a) and type (b) sequences, and the type (c) sequences wimiww and wimmiww. By deduction 3 the only type (a) sequence which may contain an F is miwiwim, the only type (c) sequence which may contain F is wimiww, and all type (b) sequences except wimmiw may contain F. Checking all the answer choices against these permitted sequences, we see that only (C) is forbidden, so this is our answer.
3. (B)
If S is fourth and there are 7 layers, the only possible sequence is the type (a) sequence miwwwim. We already know this sequence cannot contain F, so (B) is impossible and is therefore our answer.
4. (C)
We must have one of the sequences GLK or KLG. Since K is already next to L (the only other m) and may not touch wood (by rule V), it must be next to an i. By rule IV this i may not be F, so since G is already used it must be H. So we have GLKH or HKLG.
Looking at our sequence library, we see that the only sequences containing mm are wimmiw, wwimmiw, and wimmiww. However, since P is out, we only have 2 w's available, so our sequence must be wimmiw. There are no restrictions on which w is O and which is S, so we can put O first or S first, and we can put GLKH in the middle or HKLG in the middle, giving the four possible arrangments OGLKHS, OHKLGS, SGLKHO, and SHKLGO.
Therefore the answer is (C).
5. (A)
In this case we have little choice but to check the answers one by one.
(A) fails because the only sequence with m first and i fifth is miwwim, which cannot contain fleece by deduction 3. So this will be our answer, but I will confirm the others briefly anyway.
(B) L is allowed to touch G and H individually, and we have several type (b) and (c) sequences which contain imi, so GLH or HLG is possible.
(C) We have the type (a) sequence miwwwim, so OPS or SPO are possible.
(D) The type (c) sequence wwimmiw permits O (a w) to be second and G (an i) to be sixth.
(E) Several sequences permit mm, so KL or LK is permitted.
6. (no correct answer)
We can confirm that there is no correct answer by examining each answer choice and asking if there are any sequences permitted under the old rule which are not permitted under the new rule or vice versa.
(A) fails because the new rule does not permit the previously allowed sequences miwwim, miwiwim, wimmiw, and wimimiw. Sample arrangement that is allowed by the original rule but violates the new rule: OGKLHP.
(B) fails because the new rule does not permit the previously allowed sequences miwwim, miwwwim, wimmiw, wwimiw, wwimmiw, wimiww, and wimmiww. Sample arrangement that is allowed by the original rule but violates the new rule: OGKLHP.
(C) fails because the new rule does not permit the previously allowed sequences wimiwiw, wiwimiw, wwimiw, and wimiww. Sample arrangement that is allowed by the original rule but violates the new rule: OFKGPS.
(D) fails because the new rule does not permit the previously allowed sequences miwiwim, wimiwiw, and wiwimiw. Sample arrangement that is allowed by the original rule but violates the new rule: KGOFPHL.
Choice (E) isn't violated by any of our arrangements, but it allows the arrangements wmimiww and wmimiw (and mirror reflections), which violate the original condition that w does not touch m. Sample arrangement allowed by the new rule which violates the original rule: OLGKFP.
[Please prove me wrong on this one!]
7. (E)
We need to have ww and mm both in the same sequence, which means we have one of the type (c) sequences wwimmiw and wimmiww. Note that by deduction 3 neither of these may have F, so our i's must be G and H. Also, all w's and m's must be included. Since F is absent, we may arrange our w's, m's and, i's however we like in the appropriate slots. The farthest distance between any w and any i is between the first and sixth slots in wwimmiw or between the second and seventh in wimmiww. There are four layers between the elements of each of these pairs, so our answer is (E).