Mingyuns Wrote:Two question for page 252 and page 253:
1. for the diagram of drill 2, since there is no consecutive shifts for any doctors, we could conclude no P on Wed. evening and Th. afternoon. That makes there is only one P. Next inference will be cloud (O,R) on Th. afternoon and evening. Then Wed. morning and evening will be O/R. We may have two R's or R and O to fill Wed. morning and evening.
2. for the diagram of drill 3, S/W may be out. If we frame, we may have both S and W are out, which means that we may have the out part as: x/y, s, w; or x/y, s/w, r/t.
Am I right? Any corrections are welcome!
1. I'm looking very closely at the wording on #3. I'm not convinced that Wednesday Afternoon and Thursday Morning are consecutive shifts. Therefore, I see the the limitations to this game in the following way:
2. nice work! Exactly right.
Thank you for your reply. Actually, I never thought of that Wednesday Afternoon and Thursday Morning are not consecutive shifts. However, since "R will cover at least one shift before and one shift after ANY shift P Takes", P could not be on both Wed. evening and Thurs. morning. Therefore, #of P is 1.
Except that, I totally agree with your diagram. So for the diagram in page 252, we could put R/O in both Wed. morning and Wed. evening. The cloud over Thurs. afternoon and evening could include both O and R.
Here are my frames of numbers:
Frame 1: which results two arrangements.
O: 1
P: 1
Q: 1
R: 3
Frame 2: which results four arrangement.
O: 2
P: 1
Q: 1
R: 2
Also thank you for your confirmation of the latter question!