ManhattanPrepLSAT1 Wrote:
I think this game is more easily done via frames. The K, H M conditional rule creates a nice placeholder. The first time I did the game I intially thought the G_s-->L_T was a placeholder for T until I realized there is also the option of G being out. However, the final conditional rule creates a nice placeholder of FHM or K in "T". This leads us to three frames.
Frame 1:
Put HFM in T and then put K in S . You will see that this forces L into S too. Really, then, G is either in T or out.
Frame 2: Put HFM in S and K in T. In this game, the frame is left pretty open ended.. But there is really only G, L, and M left and they can be played around with pretty easily.
Frame 3: Put FHK all into "T". When you do that there is only MGL left and we need to fill in 2 slots for "S". Since L/M can not go together both into "S", this means that G must take up one slot in "S". If G is in S that triggers the conditional rule of pusing L into T. Then, with only M left M has to be in S so that S can have two elements.
FRAME 4 K out and HMF in T. In this case, it is actually not possibvle because that leaves us with GL left but both of them can not both go into the "S" group
Frame 5: Put HMF out --> not allowed since FH must always be in.
OVerall that was all the possibilties in the game. I think the game hinged on the placeholders as it made the questions easier.
Seemed quite difficult, like a hybrid of in/out and basic grouping. I think my trouble was that I couldn't figure out how to represent the THREE types of assignments (2 schools or not selected) in the context of an In/out logic chain. Plus I hit this with only about 6 minutes left, so upon seeing how tricky it was, I panicked. Yarr 
Anyone have a good diagram for this?
