by bbirdwell Wed May 12, 2010 10:26 am
Pretty straightforward setup -- there aren't many deductions to make at all. The most important one, I think, is looking at the list of barred relationships and thinking "Wow! P doesn't get along with anybody!"
Then you'll notice that P, N, and O can never go to the same place. This means that they must all go to different activities. There are innumerable ways to mark this on the diagram. You can star each of them to remind you that they can never share any, or you use dots, as I have in the attached diagram.
Taking this into account and combining it with the constraint that says we must have exactly 2s, we can see that there are only two possibilities for the distribution of activities: 2s. 2r, 1m, or 2s, 1r, 2m.
That's all I was able to do with this one. All you have to do is pay attention to P, N, O, and watch that Nm/Vm conditional and you should be fine.
Does that make sense?
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