by noah Mon Sep 14, 2009 3:36 pm
It is a complex binary grouping game since there's a third group, the presentation. I went ahead and solved it and found I didn't really use much of a diagram. I think the key to this game is two-fold: correctly conceptualizing the game (requiring that you understand each constraint), and making some initial inferences.
The big inference for me is that with such a large group of male Parakeets, it's not possible to put them into two cages, at least one of them needs to be presented, which requires that one female be presented as well. So after that it becomes a question of making sure that whoever else is presented has it's opposite gender mate, and that no same-sex-same-species pairs are in any cage together (which is easy, since there are no other triplets).
I put together a rather involved diagram, attached, but honestly I think this is a case where it wouldn't help that much. One could go even further with this diagram, putting in, for example, that if H is presented, then one of J/K must be in a cage, or that if Q and Q is presented that S must be in a cage, but these are easy deductions to make while dealing with questions. By the way, in the diagram, "+" means male, and the brackets mean any one of the members of that group (though there's a caveat with the J,W, S rule).
What do you think?
- Attachments
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- PT14, S1, G3- Birdcage and Exhibit - ManhattanLSAT.pdf
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