Diagram

[h.b.]

Hi,

Can someone please post the set up for this game? It was done during the study hall and I missed most of it due to bad connection...

Thanks!

[aileenann]

Here's what we came up with in our studyhall -- a very strange game! Take a look and see how it works for you. It's definitely a tight chain.

Tell me what you think.

[nazu.s.shaikh]

Question,( Thank you for the diagram btw, very helpful!) If O is at S then P should be at R .. right? So then for Q19 how can both P and O be at S together?

Also for 23.... J and K cannot both be at R.One has to be at the other (S) so why is A incorrect?

[dan]

Be careful that you don't read the arrows backwards. The arrow goes from P(r) to O(s), not the other way around. The PDF diagram above is a bit hard to read, so maybe you misread it as a double-sided arrow?

For #23, J and K CAN both be at R. Again, be careful not to read the arrows backwards. It's true that they can't be at S, but they can both be at R.

Hope that helps!

[rachael.swetnam]

I could use some help understanding #22 and #19.
thanks so much.

[mturner]

Rachel,
It took me quite a while to figure out # 19 as well and I got # 22 correct by dumb luck ( I have diagrammed my rules wrong). Anyway, after redoing my diagram and spending close to an hour on the questions, I figured them out.

# 19: Looking at the rules, if O is in S, then N must be in S. That eliminates answers A and C. N and P can't be in R together, but nothing keeps them from being in S together. So, right now we have at least O, N, and P. So, now we have eliminated answer D and E leaving answer B. However, I saw in the rules that if J is in S, then K is not and I don't see K in answer B.

Kind of a round about answer, but I was able to get it right.
Now for question # 22: I set up two charts placing N and O in both columns. When I placed O is column S, then by the rules N had to be in S as well. So, the only diagram that would work is N being in S and O being in R. Then, if you look at the rules, if O is in R, then J must be in S--answer A.

[ManhattanPrepLSAT1]

Nice work mturner...

Let me just add another way of looking at Q19. This is an orientation question. Simply take the constraints and knock out the incorrect answers one by one. Compare each constraint against the answer choices.

To see the process...

(A) violates the 1st constraint
(B) is correct by the process of elimination
(C) violates the 4th constraint
(D) violates the 5th constraint
(E) violates the 2nd constraint

For Q22 take a look at the following frames that can be established based on establishing one frame where J is at Souderton and one frame where J is at Randsborough. I would have these frames established before I even started on the first question.



And let me know if you still have questions on this game...

[peg_city]

How do you approach 21? Can you still use the diagram presented?

Thanks

[nborges]

Hello,

I am also interested in the best approach to figuring out question 21.

Thanks!

[kylelitfin]

Hello,

I am also interested in the best approach to figuring out question 21.

Thanks!

Question 21 should actually be really quick. If you don't already have a really strong set of chains made a quick glance at the rules show that condition 5 can potentially cause the most issues with getting a low number of doctors in S.

Pr -> Ks + Os
Or or Kr -> Ps

Well obviously we don't want to throw 2 doctors into S right off the bat, so we're going to use the contrapositive as our starting point creating this:

Moreover, even if you did go with Pr -> Ks + Os, you're going to force the contrapositive of 4, Os -> Ns and all of the sudden there are 3 doctors in S without even looking at the other rules.

S --> P
R --> O, K

From here, just go through the conditions in order:

Condition 2 contrapositive: Or -> Js

S --> P, J
R --> O, K

Condition 3 contrapositive: Ns or Ps -> Lr

S --> P, J
R --> O, K, L, N

Done. 2.