by ohthatpatrick Fri Aug 12, 2016 6:56 pm
Forgive the visual challenges of getting things to look right in this typing space. I may have to use "...." to space things into the proper spot. Ignore those dots.
We have 4 things for 7 spots. MISMATCH!
Are we using all spots? Yes, there's a voyage every week.
Do we have to use all the things? Yes, each destination will go at least once.
So, we could potentially fill up 7 spots with 4 things with combos like
1 1 1 4
1 1 2 3
1 2 2 2
(But it would be hasty to do that so soon ... we'll probably get rules that limit what's possible)
Our basic diagram is
G J M T
__ __ __ __ __ __ __
1.. 2. 3. 4. 5. .6. 7
Checking out the rules:
J can't be 4.
T must be 7.
M goes exactly twice, with at least one G in between
M - G+ - M
J --> GJ ("any" is a conditional trigger word)
Can't ever do GG, JJ, MM, TT
G J M T
__ __ __ __ __ __ T
.............~J
Anyone mentioned more than once?
G and J ... so they are priorities
Anyone never mentioned?
All were mentioned. No floaters.
Anything frame-worthy? (Chunks or significant either/ors?)
Not really. The only chunk is the GJ, and it MUST occur at least once, since J must go at least once.
There are theoretically 4 options for the GJ chunk, since it could be 1/2, 2/3, 4/5, and 5/6
(J can't go on 4, and 7 is already saved for T).
If you like framing, then frame those four options:
G J _ _ _ _ T
_ G J _ _ _ T
_ _ _ G J _ T
_ _ _ _ G J T
the next most meaningful rule is the M - G - M rule.
Let's see if we know where M's are going (use clouds if you're not sure where but know which side of GJ it's on).
G J _ _ _ _ T (we would draw an M - G -M cloud over spots 3 thru 6 .. can't do it here)
M G J _ _ _ T (we would draw a cloud with an M over spots 4 thru 6)
_ _ _ G J M T (we would draw a cloud with an M over spots 1 thru 3)
_ _ _ _ G J T (we would draw an M - G - M cloud over spots 1 thru 4)
That's if you're frame happy, no need otherwise.
What about our numbers?
1114
1123
1122
The first one is out, since M = 2.
1123
1222
Do we know anyone else who can/can't go 2 or 3 times?
T basically is fine anywhere but 6. He can probably go 2 or 3 times.
G can probably go 2 or 3 times. Just one has to be in between the M's.
J might be able to go twice. Tricky, because we'd have to GJ's. But theoretically possible, because that would be a 1222 scenario.
That's more setup than I should probably even have shown. On a real test, I would have looked at this hodge podge of rules and thought, "Let's just go to the questions ..."
Hope this helps.