Diagram

[jas770]

Could someone explain this game? I have no idea how I should tackle it. Thanks!

[ManhattanPrepLSAT1]

Good game! I've attached a setup to help you see one possible way to organize the information. Additionally, I went through question 7 to help you get started on the questions.

If you still need further help with this game (it's tough!) let me know. I'd be happy to help!

[interestedintacos]

Is there a reason to expect a mapping game like this in next June's LSAT?

[ManhattanPrepLSAT1]

No reason other than that every once in a while they keep bringing games back from the past that we haven't see for a while. In 2003, we saw both a circular ordering game and a game similar to this. Check out:

PT41, S2, G4
PT40, S2, G3

So while, it's highly unlikely, I cannot say it's impossible to see a game like this radar game. So prepare, but don't over do it...

[mcrittell]

I diagrammed this correctly, but I'm having trouble discerning what it means to be in an area. Like, if J is in S, does that mean it's in T as well because they intersect? Can J be in S, and not connect with T? Being in U would mean that you're in 3 right (R, U, T)?

[timmydoeslsat]

I diagrammed this correctly, but I'm having trouble discerning what it means to be in an area. Like, if J is in S, does that mean it's in T as well because they intersect? Can J be in S, and not connect with T? Being in U would mean that you're in 3 right (R, U, T)?

This was my diagram when I just did this game.



You are correct in saying that if you are in area U, you are also in area R and T by necessity.

We do know that J is in S. However, do we not know if it is the part that intersects with T or not. It could be true according to the rules that it is in the part with intersects with T. We would know however, that if J is in the part where S and T intersect, it could not be the case that K is in area, S, T, or U. K would have to be in the area of R that does not intersect.

Please tell me if you understand it now.

[mcrittell]

For example, 12. Why can't E be correct.

Why can't L be a part of R that doesn't the intersection, K be in U, M be in the part of T that doesn't intersect, and have J and L be in the section of S that doesn't intersect?

[timmydoeslsat]

If you put L in just R, it would not be in two areas!

If we have M in T, we know that L cannot be in area T. Thus, it could not be in the intersection of T and R or T and S, or even U because it is within T.

L can go in non-intersecting part of R or a non-intersecting part of S. However, it could not be in those intersections because those intersections include T. Thus, it must be false that L is in exactly two areas.

[mcrittell]

within 2 areas=intersection, then, rt?

and in 2 areas=does this mean 2 separate areas then?

[timmydoeslsat]

within 2 areas=intersection, then, rt?

and in 2 areas=does this mean 2 separate areas then?

It is physically impossible for a plan to be in 2 separate areas.

The only way for a plane to not be in just one area is if the plane is in an area that intersects.

[tara]

This is making me crazy. The game specifically says that there must be at least one plane in each zone. And yet -

Question 7, answer is D, even though there is no plane in zone U??

Can someone help explain this please??

[timmydoeslsat]

This is making me crazy. The game specifically says that there must be at least one plane in each zone. And yet -

Question 7, answer is D, even though there is no plane in zone U??

Can someone help explain this please??

The rule states that each plane is in at least one of the four areas.

So, based on that rule alone in isolation, would allow for all four planes to be in one area. You can validly have the other three areas not being used. The concern with that rule is that each plane is being used, not the areas.

To complete question 7.

A) Does not have K listed, which breaks our first rule.
B) J is not in Area S, which breaks our second rule.
C) M is in Area U, which breaks our fifth (last) rule. M is in exactly 1 area. We know that Area U is totally within R and T at the same time, this means that M would be occupying three areas, and not one.
E) J and K are in the same detection area, which breaks our third rule.

[ttunden]

Can someone please elaborate on why M cannot be in area U?

Per the rules U is its own detection area. If M is in U, then it still satisfies the rules right? Because U is its own area technically speaking. I don't understand how the test writers equated Area U = Area T and R.

Yes, I do understand that area U is within areas T and R but area U is still its own area. Surprisingly, I still got a vast majority of the questions right even missing this key inference. After watching 7sage and reading the explanations here, I still do not understand how this inference was derived.

If anyone could explain, I would greatly appreciate it.

Thanks

[ttunden]

Can someone please elaborate on why M cannot be in area U?

Per the rules U is its own detection area. If M is in U, then it still satisfies the rules right? Because U is its own area technically speaking. I don't understand how the test writers equated Area U = Area T and R.

Yes, I do understand that area U is within areas T and R but area U is still its own area. Surprisingly, I still got a vast majority of the questions right even missing this key inference. After watching 7sage and reading the explanations here, I still do not understand how this inference was derived.

If anyone could explain, I would greatly appreciate it.

Thanks

just wanted to bump this for a response

[sulee12]

Hi,

To answer your question ttunden you have to go back to the rule "M is in exactly one of the areas" which means that M is only in one spot. According to the stimulus, U is totally within R and T which means that everything that is in U is also in R and T. Now, if you put M in U, M is automatically in R and T which violates the last rule that I talked about. Hence, M cannot be in U.