by ManhattanPrepLSAT2 Tue Jul 27, 2010 9:18 pm
#12 is an orientation question -- generally you can answer this type of question most efficiently by using the constraints one at a time to eliminate answer choices.
The first constraint eliminates B.
The second constraint eliminates E.
The third constraint eliminates C.
And the final constraint gets rid of D.
#14 is a conditional question, so you should expect to make a lot of inferences before you move on to the answer choices.
If T is fifth and F is sixth...
O must be first (because it can't be fifth).
R must be second or third (because it must be at least 3 slots away from F)
Now let's think about S -- we know, based on the q stem, that it can only go in two slots -- which ones are the most likely?
Let's try slot 7 -- can we put S there? Don't see why not. Doesn't violate any conditions that S is involved with, and it seems like there will be no issues fitting the other elements into the other slots.
Let's try slot 4 -- can we put S there? Well, we know P has to be before S, and R has to be in slot 2 or 3, so we know P and R have to occupy 2 and 3. With S in 4, that would put L or H in 7, and L or H in 8. That seems fine too.
Let's try slot 3 -- if S is in slot 3, P would have to go in slot 2, and there would be no place for the R. Therefore, S can't go in slot 3.
#15 is another conditional question -- let's see what we can figure out from the condition that O is immediately after T before we go to the answer choices...
We know that this must mean O is fifth (if O is first, T can't be in front of it) and therefore, T must be fourth.
Moving on, since we know that O follows T, it must be true that R precedes T. Therefore, we know R must be third.
F must be at least 3 slots away from R. It can't be in front of R (not enough space) and to be at least 3 slots behind R, it would have to be in either slot 6 or 7.
Therefore, (E) is the correct answer.