Diagram

[ebrickm2]

I need them, plox!

[ManhattanPrepLSAT1]

Here's the setup for this game!

Good luck...



And you can find the setup for game three at the following link.

http://www.atlaslsat.com/forums/pt25-s3 ... t1003.html

[opulence2001]

Hi,

The only trouble I had with this game was question 5. I t says" The largest number of members that the planting committee and the trails committee could have in common is..."

I know that three out of four of the members for each team could match. One team will have four members because it has to have M, and the other committee will have just three (all three on that team will match the other). For example:

Plants : KJL
Trails: KJLM

It would seem that three members are in common here.

I didn't understand how the answer could be D. How can they have six members in common? Each committee can only have up to four members.

Even in the rules it says the two committees must have one member in common, meaning that one member is on both teams.

Please help!

[farhadshekib]

Hi,

The only trouble I had with this game was question 5. I t says" The largest number of members that the planting committee and the trails committee could have in common is..."

I know that three out of four of the members for each team could match. One team will have four members because it has to have M, and the other committee will have just three (all three on that team will match the other). For example:

Plants : KJL
Trails: KJLM

It would seem that three members are in common here.

I didn't understand how the answer could be D. How can they have six members in common? Each committee can only have up to four members.

Even in the rules it says the two committees must have one member in common, meaning that one member is on both teams.

Please help!

Each committee must have AT LEAST THREE members, and the two committees must have AT LEAST ONE member in common .

This does not mean, however, that each committee can only have up to 4 members.

Also, keep in mind that the rules do not state that all members have to be selected.

In question number (5), (D) is the correct response.

Committee T:
H, G, M, L, J and K

Committee P:
H, G, M, L, J, and K

This meets all the requirements: 1) at least 3 members are in each committee; 2) F and K are not on the same committee; 3) K --> KJ is present; 4) M is on at least one committee; and 5) the two committees have at least one member in common.

In fact, they can have all 6 members in common. The only member that cannot be included is F because that would violate the F/K rule.


Hope this helps

[rpcuhk]

Here's the setup for this game!

Good luck...

PT25, S3, G1_AtlasLSAT.pdf

And you can find the setup for game three at the following link.

http://www.atlaslsat.com/forums/pt25-s3 ... t1003.html

I think I found a mistake in the main diagram
the condition M must be on at least one committee should be diagrammed as
~Mp-->Mt
your diagram
Mp-->Mt seems odd

[ManhattanPrepLSAT1]

I think I found a mistake in the main diagram

You're so right! Thanks for catching that. I've gone back, edited the constraint, and reposted it above.

Thanks!

[dtemple2]

I am having a hard time understanding #2 . Why can't you replace F with K? That would make the Planting Committee K,J,H,L,M and the Trails G,H,J. Each has at least 3 members, F is not with K, K is with J, M is on at least one committee and the two committees share at least one member.

Also, in your diagram you indicate that no more than 5 members can be in a committee. However even question #5 shows that you can have up to 6 members in a committee.

Pleas help!

[timmydoeslsat]

I am having a hard time understanding #2 . Why can't you replace F with K? That would make the Planting Committee K,J,H,L,M and the Trails G,H,J. Each has at least 3 members, F is not with K, K is with J, M is on at least one committee and the two committees share at least one member.

Also, in your diagram you indicate that no more than 5 members can be in a committee. However even question #5 shows that you can have up to 6 members in a committee.

Pleas help!

In regards to the diagram, you are correct in your concerns. I would say that the diagram is inaccurate.

In regards to #2, the problem you are having appears to be with the question wording itself. The hypothetical you pose of "K,J,H,L,M" as the planting group would not match the group you were given in the question stem.

We are told that these are the groups:

P: FHLM
T: GHJ

You could not plug in K anywhere in the planting group. Doing so would violate the K ---> J rule. We are asked that K could replace which one of the variables in the two groups without violating any rules. Attempting to replace F with K would be impossible without also putting J in there, which is not the setup.

So since we cannot have K replace anyone in the top group, that removes FLM. I keep H in mind for the bottom because it is still a contender at first consideration until we realize that at least 1 of 2 things will occur:

1) You remove the common variable in the two groups.
2) You place a K in the planting group without the J being present.

So we now have FHLM gone from consideration. G is the only one left. We can easily replace it with K. We already have a J there. The common variable still remains.

[dtemple2]

You are absolutely right. I cannot believe I did not initially see this. For some reason I had it so ingrained that J follows K and so if you replaced F with K, J would automatically follow. Very silly error on my part but thank you for your reply. I really appreciate it!