by tommywallach Thu Oct 25, 2012 12:51 pm
Hey Naresh,
Turns out questions like this really stress people out, because you can't actually know whether the interior square touches on the midpoints of the bigger square. But you must know that it COULD touch the midpoints of the bigger square. So basically, picture a diamond inside a square, touching at all the midpoints of the square.
From here, you can see that you've created four right triangles in the corners of the bigger square. These triangles are 45/45/90 triangles, and their two perpendicular sides are both equal to half the length of one side of the big square. So if big square has sides of 10, then the triangle has perpendicular sides of 5. This means that the hypotenuse is 5 rt. 2, which equals one side of the smaller square. So the least possible area is (5 rt. 2)^2, or 50.
Let me know if I missed something, but I don't see that I did. Also, where is this question sourced from?
-t