by n00bpron00bpron00b Fri Mar 13, 2015 3:43 pm
I hope I am answering the right question :). Is it the one where we have to compare Quantity A - "x" and Quantity B - "y" - and the diagram contains variables "x" & "2y" placed on either side of the line :D
1st - Don't fall into the trap of assuming on geometric questions - proceed ahead on the basis of what information is given and what can be deduced from it
2nd - It is no where stated that the diagram is an rectangle or square or if the bisecting line is a diagonal
Some of the ways be can prove it as an square -
-> All angles should be 90
-> All sides must be equal or a
Rhombus with two angles 90 and so on
Similarly, for rectangle
-> All angles should be 90
-> Opp sides equal and so on
Now the solving part -
a) We cannot assume angle x and y as 45 each, just because the line looks like a diagonal, for the matter of fact the given diagram may not even be a rectangle or square. We have no valid basis to assume anything.
b) Start with what is given - i.e
If you notice the upper right 90 degree triangle -
-> One angle is 90 (given)
-> One side of 90 degree angle has length = "1"
-> Side opp the 90 degree angle has length = "2"
We can use the Pythagorean theorem to find the 3rd side
Let the third side be "p"
(1)^2 + (p)^2 = (2)^2
1 + p^2 = 4
p^2 = 3
p = square root of 3
Okay, now we have a triangle with three lengths
1, square root of 3 and 2
If you notice these lengths (1,sq root 3, 2) are nothing but 30-60-90 special right triangle.
30 - 60 - 90 => lengths => 1,sq.root 3,2
From above we can conclude - the angle opposite ("x") side length 1 is 30 degrees
so x = 30 degrees
If x is 30 degrees then 2y is 90-30 = 60 degrees
If 2y = 60
y =30
x = 30
y = 30
"C"