A fair 6-sided die is rolled twice.
Quantity A
The probability of rolling the same number both times.
Quantity B
The probability of rolling two different even numbers.
My reasoning told me that Quantity A should be 1/6 x 1/6 = 1/36
and
Quantity B:
We've got 2 different even numbers in a die - 2,4 and 6.
The probability of getting one of these in the first roll would be 3/6 and then the probability of getting a second one (different from the first one) would be 2/6. Thus 6/36 or 1/6.
Answer: C (both equal)
Can someone point out if my reasoning is correct and whether there is a shortcut to solving this on the test day.
many thanks :)