The area of triangle ABD is larger than the area of triangle BCD.
Quantity Alength of AD
Quantity Blength of CD
(Not sure if the image pasted above) Nonetheless, I don't believe there is enough information here to solve. The solution argues that because the heights are equal, (1/2)(AB)(H)>(1/2)(BC)(H). Which leaves AB>BC, which I understand. But who is to say the the heights (H) are equal? In order for the height to be equal, it must be given that the larger figure, (ADC) is indeed a triangle. It looks like a triangle, but we need to be told that. We are told nothing about angle DBC, which is drawn to look like 90 degrees, but if it were to be, say 100 degrees, then the heights aren't equal, and CD could be greater than AD.
Thoughts?