I know that the way to answer this is to 1) calculate the probability of never landing on an even number through two rolls and then 2) subtract it from 1:
1/2 x 1/2 = 1/4 chance of never landing on an even number
1 - 1/4 = 3/4 chance of landing on an even number at least once
However, though I know how to simply answer the question, I think I don't fully understand some of the underlying concepts.
By similar math, there is a 3/4 chance of landing an odd number at least once. Thus, the probabilities of at least one even number or at least one odd number are the same. So, I understand how the math leads to this outcome -- but what is the best way to understand how these probabilities co-exist? Here's where I get confused:
- The probability of landing a die on an even or odd number at least once, through any amount of rolls, has to be one 1.
- However, the two events described above are independent events. Thus - to determine the probability that landing on an even number at least once and landing on an odd number at least once will both occur - I multiply the two probabilities together: 3/4 x 3/4 = 9/16.
- Additionally, these two outcomes may be understood as non-mutually exclusive "or" probabilities -- i.e., at least one even or at least one odd - meaning that their shared probability may be calculated as P(even) + P(odd) - P(even and odd): 3/4 + 3/4 -9/16 = 15/16