In the (x,y) plane (1,2) is on line j and (2,1) is on line k. Each of the lines have a positive slope.
Quant A Quant B
Slope of line j slope of line k
Why is the Ans D. Drawing the figure indicates line j should have a steeper slope than line k.
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- hasibul212003
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- n00bpron00bpron00b
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Re: Powerprep 2 Test 2,Section 3,Q5.
case 1:
point (1,2) on line J
point (2,1) on line K
both positive slopes (so both the lines must pass through quadrant 1 and 3)
If we extend it up and down in it's place itself. Line J will have greater slope (since it is more steep compared to Line K)
A>B
Case 2:
Keep line K as it is
Imagine the line J at an approx angle say 30 degree going from quadrant 3 to quadrant 1 and passing through the point (1,2)
In this case line K becomes more steep and has greater slope
So B > A
hence D
point (1,2) on line J
point (2,1) on line K
both positive slopes (so both the lines must pass through quadrant 1 and 3)
If we extend it up and down in it's place itself. Line J will have greater slope (since it is more steep compared to Line K)
A>B
Case 2:
Keep line K as it is
Imagine the line J at an approx angle say 30 degree going from quadrant 3 to quadrant 1 and passing through the point (1,2)
In this case line K becomes more steep and has greater slope
So B > A
hence D
- tommywallach
- Manhattan Prep Staff
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Re: Powerprep 2 Test 2,Section 3,Q5.
Great explanation here.
Just to be clear, remember that all you have is one point. You can draw a line with LITERALLY any positive slope that will go through one point. It's only when you have TWO points that the slope is defined already.
-t
Just to be clear, remember that all you have is one point. You can draw a line with LITERALLY any positive slope that will go through one point. It's only when you have TWO points that the slope is defined already.
-t
- kpkanupriyakhmi
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Re: Powerprep 2 Test 2,Section 3,Q5.
I didn't get this line:-Imagine the line J at an approx angle say 30 degree going from quadrant 3 to quadrant 1 and passing through the point (1,2)
- n00bpron00bpron00b
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Re: Powerprep 2 Test 2,Section 3,Q5.
In case 1 : slope of line J was greater as compared to slope of line K
we need to contradict the above answer to prove "D"
To make slope of line J less than slope of line K -> we have to make line J less steep
Consider this (just an approximation)
Line J passing through points (-7,3) and (1,2) - steepness decreases (almost falling down position) - in such a case slope of line K is greater
hence D
we need to contradict the above answer to prove "D"
To make slope of line J less than slope of line K -> we have to make line J less steep
Consider this (just an approximation)
I didn't get this line:-Imagine the line J at an approx angle say 30 degree going from quadrant 3 to quadrant 1 and passing through the point (1,2)
Line J passing through points (-7,3) and (1,2) - steepness decreases (almost falling down position) - in such a case slope of line K is greater
hence D
- tommywallach
- Manhattan Prep Staff
- Posts: 1917
- Joined: Thu Mar 31, 2011 11:18 am
Re: Powerprep 2 Test 2,Section 3,Q5.
Hey Kp,
Yeah, in general, when all else fails, ignore the explanation in the book and try to understand my/Noob's explanations. I think we do a better job!
Does it not make sense that you can draw ANY line that only goes through one point? It can have any slope whatsoever...
-t
Yeah, in general, when all else fails, ignore the explanation in the book and try to understand my/Noob's explanations. I think we do a better job!
Does it not make sense that you can draw ANY line that only goes through one point? It can have any slope whatsoever...
-t
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