Hi,
Any Help will be greatly appreciated :)
Q.8) Pg.166 Medium Problem Set (difficulty in understanding the logic behind the sum)
Q.9) Pg.170 : 2nd Edition : Hard Problem Set
If x^2/4 is an integer greater than 50 and X is an integer, then what is the smallest possible value for X^2 ?
Although I have got the right answer, Please let me know if it's the right way of approaching such types of sums .
Solution:
Step1: Since x is divisible by 4 : x has to be multiple of 4 (4,8,12,16,20..)
Step2: x being multiple of 4 : x^2 is multiple of 4 (i.e 16,64,144,256,400..)
Step3: 256/4 = 64
In addition, given the case if x is not an integer. Could you please let me know how does one get the answer 204.
The question states x^2/4 is an integer greater than 50 ; by property of divisibility "On dividing an integer by another integer if the result/quotient is an integer then integer 1 is divisible by integer 2 ; does this not automatically make x or x^2 an integer value ? (as the problem mentions the result is an integer)
I am not quite sure how to treat x^n terms/divisible by something, facing similar problem in Q18 Pg.171 (could you please explain this sum too.)
Q.2) Pg 165 : Medium Problem Set
x/100 is an integer
Quantity A: x^3
Quantity B: x^2+100
The guide states "Question related to divisibility are only interested in positive integers". Should I be keeping in mind negative multiples/factors as well ?
Q17) Pg.171 : Hard Problem Set
b,c,d are consecutive even integers such that 2<b<c<d. What is the largest positive integer that must be a divisor of bcd.
Soln. I believe, the question is asking for the largest positive factor of bcd
Using LCM and the condition 2<4<6<8
4: 2 x 2
6: 2 x 3
8: 2 x 2 x 2
LCM : 2x3x2x2x2 (basic building blocks for the numbers after prime factorization of 4,6,8)
And hence 48
Was unable to get the explanation given in the book, I hope the above method is right.
Apologies for the long post.
Thanks,
-X