Hello Sir,
Recently I went through a math problem and i couldnt get a solution for it... It is really tempting me a lot.... The question goes like this
(((100!-99!)^100)-((99!-98!)^100))/((98!-97!)^100)
Help is appreciated......
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- vijayvinay93
- Students
- Posts: 1
- Joined: Sun Mar 10, 2013 6:04 pm
- tommywallach
- Manhattan Prep Staff
- Posts: 1917
- Joined: Thu Mar 31, 2011 11:18 am
Re: Factorial problems
Hey Vijay,
We only accept questions on this forum that are presented as real GRE questions. In other words, you need to present either 5 answer choices (for normal problem solving), or else two columns (if it's quantitative comparison), or else you can say it's a direct entry question, which I doubt something like this would be.
However, it can be simplified as:
(100^100 - 99^100) / 98^100
Then we can separate it into two fractions:
100^100 / 98 ^ 100 - 99^100 / 98^100
But from there, I'm not quite sure what we would do. Of course, a real question would have answer choices. This might be as far as they expected us to take it. Do you have answer choices here?
-t
We only accept questions on this forum that are presented as real GRE questions. In other words, you need to present either 5 answer choices (for normal problem solving), or else two columns (if it's quantitative comparison), or else you can say it's a direct entry question, which I doubt something like this would be.
However, it can be simplified as:
(100^100 - 99^100) / 98^100
Then we can separate it into two fractions:
100^100 / 98 ^ 100 - 99^100 / 98^100
But from there, I'm not quite sure what we would do. Of course, a real question would have answer choices. This might be as far as they expected us to take it. Do you have answer choices here?
-t
2 posts Page 1 of 1