by tommywallach Fri Oct 14, 2011 1:25 pm
Hey Agha,
They key is to realize that if you drop a height and know that length, you can build a right triangle WITHIN the parallelogram, the hypotenuse of which is the parallelogram's diagonal. In the example you cite, try dropping a height from point B. This now creates a right triangle with height 4 (because they tell you that on the right side of the diagram), and a base of 12. Pythagoras will then solve you to the diagonal.
Make sense?
-t