can pls someone explai me this

[123aster]

5A
BC
=
D43


8. In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

A. 23
B. 22
C. 18
D. 16
E. 14

[tommywallach]

5A
BC
=
D43


Hey 123aster,
Well, immediately we know that D = 1, because two two digit numbers can't get above 199.

This means that we're adding up to 143.

Now let's just try stuff

50 + 93 (not allowed cuz repeat 3)
51 + 92 (not allowed because repeat of 1)
52 + 91 (not allowed because repeat of 1)
53 + 90 (repeat 3)
54 + 89 (repeat 4)
55 + 88 (repeat 5, 8)
56 + 87 (IT WORKS!)

So our A B C D are 6 + 7 + 8 + 1 = 22

Hope that helps!

-t