Errata – Algebra, 2nd Edition
Cover for 2nd Edition
2.0
| Page | Location | Description | Erroneous Text | Correction |
|---|---|---|---|---|
| 34 | Bottom | Subtraction result (last line) | = 12 | 4 squareroot[(x – 6)] = 12 |
| 42 | Top | #8, first line of solution, right of : sign. Subsequent calculations are correct. | [11 – 3(x + 4)] / (x – 3) = 7 | [11 + 3(x + 4)] / (x – 3) = 7 |
| 56 | Middle | Factoring of x2 + 3x – 10 | (x – 5)(x + 2) | (x + 5)(x – 2) |
| 58 | Bottom | logic/correctness | our solutions are NEGATIVE 3 and NEGATIVE 4 | our solutions are NEGATIVE 3 or NEGATIVE 4 |
| 73 | Middle | #7 | the height, H, | the height in meters, H, |
| 73 | Middle | #7 | (how fast Hugo throws it when it leaves his hand) | (how fast, in meters per second, Hugo throws it as it leaves his hand) |
| 73 | Middle | #7 | time it takes to hit the ground. | time it takes to hit the ground, in seconds. |
| 76 | Top | #8, “L” computation | Squareroot7 × Squareroot7 = -7 | -Squareroot7 × Squareroot7 = -7 |
| 91 | Bottom | Grammar | only scenarios which produce positive products. | only scenarios that produce positive products. |
| 97 | Top | #27 explanation | a can be positive or negative, | a can be positive, zero, or negative, |
| 97 | Top | #27 explanation | so ab can be positive and negative. | so ab can be positive, zero, or negative. |
| 120 | Middle | #11 explanation | S2 = (10.5 + S2)/2 | S3 = (10.5 + S2)/2 |
| 140 | Top | #4 answer | j = 0 OR k = 4 | j = 0 AND/OR k = 4 |
| 140 | Top | #5 answer | x = 0 OR y = 0 OR x = -2 | (x = 0 OR -2) AND/OR y = 0 |
| 159 | Middle | #15 (resulting quadratic is not easily factored with printed numbers) | Administrative law: 16% | Administrative law: 15% |
| 165 | Top | Inaccurate language: colloquial use of “difference” vs. mathematical definition of “difference.” | Thus, x – y is the difference between Quantity A and Quantity B | Divide both Quantities by (x + y) to cancel that common positive factor. Now compare Quantity A: (x – y) to Quantity B: 1. |
| 169 | Bottom | Last sentence | solving first for y and then using that value to find x and z. | solving first for x and then using that value to find y and z. |
| 176 | Top | #15 explanation | 21 + x2 + (x + 1) + 16 + 22 + 17 + x = 100 | 21 + x2 + (x + 1) + 15 + 22 + 17 + x = 100 |
| 177 | Middle | #19 explanation of Choice D | (7 is larger than 2) | (7 is larger than 4) |