Errata – 5 lb. Book, 2nd Edition
Cover for 2nd Edition
Release Date: June 15, 2015
2.0
| Page | Location | Description | Erroneous Text | Correction |
|---|---|---|---|---|
| 23 | Bottom | #5, 4th line from bottom of page | “While once,” signlas that … | The phrase “while once” signals that… |
| 24 | Top | #6, 8th line from top of page | Neither works here. | Neither meaning of “incendiary” works here. |
| 53 | Top | #35, Blank (i) (A) | averse | adverse |
| 54 | Middle | #41 (E) | adequate | enjoyable |
| 70 | Top | #107, 1st line | … at best; but after… | … at best, but after… |
| 79 | Top | #1, 1st line | Football, which is by far the most popular sport in Europe. | You are told that football is by far the most popular sport in Europe. |
| 86 | Top | #38, last line | “Impudent,” then, is the correct choice. | “Garrulous,” then, is the correct choice. |
| 86 | Bottom | #41, 2nd line from bottom of page | “Adequate” and “immutable,” meaning unchangeable, do not match the desired meaning. | “Enjoyable” and “immutable,” meaning unchangeable, do not match the desired meaning. |
| 88 | Middle | #51, 2nd line from bottom | … “inundate” means to overwhlem… | … “inundate” means to overwhelm… |
| 89 | Bottom | #58, 8th line from bottom of page | “can’t ill-afford” | “can ill-afford” |
| 97 | Middle | #96, 1st line | … policitians… | … politicians… |
| 97 | Middle | #96, 2nd line | … because… | … “because”… |
| 98 | Middle | #102, 5th line | … between to known points… | … between two known points… |
| 111 | Bottom | #11 (D) | redoubtable | auspicious |
| 126 | Middle | #68 (D) | tonality | harmony |
| 142 | Middle | #132 (E) | run-of-the-mill | mundane |
| 150 | Top | #20, 6th line | Only “triage” (think of what emergency room physicians do)… | Only “triage” (think of what emergency nurses do)… |
| 151 | Middle | #27, 3rd line | “assayed” | “irrefutable” |
| 153 | Middle | #39, last line | (Insert text at end of explanation) | It is true that “prophetic” can also mean “characteristic of prophets,” and many prophets in various religious traditions spoke out against what they saw as evil governments. However, the interpretation of “prophetic” as “resisting evil authority” is not what is found as even a secondary definition in standard dictionaries. More importantly, even if you accepted this definition, there is no synonymous or near-synonymous partner among the answer choices. Sentence Equivalence questions require two answers that produce equivalent sentences. Only “pacific” and “conciliatory” work. |
| 157 | Middle | #62, 6th line | “psyched” | “enthusiastic” |
| 157 | Middle | #64, 1st line | than | then |
| 158 | Middle | #68, 2nd line | “Tonality” means relating to a particular harmonic tone and | In addition to the word “harmony” itself, |
| 161 | Middle | #85, 2nd line from bottom | “ammorality” | “amorality” |
| 165 | Bottom | #113, 2nd line from bottom | “incongruous” (not in harmony with the surroundings) | “distinguished” |
| 169 | Top | #132, 1st line | Quotidian, run-of-the-mill. | Quotidian, mundane. (Also make this change throughout the rest of the explanation.) |
| 180 | Middle | #11 (B) | Britain has caused corruption in governments throughout its former colonial empire. | Britain has caused corruption in governments other than Antigua’s through its former colonial empire. |
| 192 | Bottom | #40 (A) | The artist did not color between the lines. | The artist avoided the constraint of coloring only between the lines. |
| 200 | Middle | #56 (C) | It featured a temple-chamber. | It was featured on a temple-chamber. |
| 201 | Middle | #57 (C) | It is possible to create a coherent short story collection if the stories take place in vastly different times and places. | It is possible to create a coherent short story collection if the stories take place in different times and places. |
| 202 | Middle | #59, first line | Which of the following statements is not in contradiction… | Which of the following statements are not in contradiction… |
| 202 | Middle | #59 (C) | Adam Smith… | Adam Smith’s work… |
| 204 | Top | #63, 1st line of passage | … 1960s and 70s… | … 1960s and ’70s… |
| 208 | Middle | #71 (A) | A skateboarder grabs onto the back of a car and is able to travel effortlessly for over a mile before letting go. | The population of game birds in a state park declines sharply when hunting quotas are observed by only some hunters. |
| 225 | Middle | #107, 1st line | … disadvantage… | … disadvantages… |
| 244 | Top | #148 (E) | Atomic nucleii… | Atomic nuclei… |
| 262 | Bottom | #40, 3rd line | For choice (B)… | Therefore it is true that the artist avoided the constraint of coloring only between the lines. For choice (B)… |
| 265 | Bottom | #59, 4th line from bottom | The second statement is correct because Rothbard says that Smith’s book “eclipsed public knowledge” of better economists, meaning it had an influence that it shouldn’t have. | The second statement is correct because Rothbard says that Smith’s book “eclipsed public knowledge” of economists that Rothbard regarded as better than Smith. This is consistent with the idea that The Wealth of Nations should not have been as influential as it was—or, at the very least, does not contradict the idea that The Wealth of Nations should not have been as influential as it was. |
| 267 | Middle | #70, 4th line | Choice (C) is incorrect becasue… | Choice (C) is incorrect because… |
| 267 | Middle | #71, 1st line | (Replace entire answer explanation) | The first statement is correct because some hunters are taking more game birds than they should, causing the population of those birds to decline. The second statement is wrong because the free rider problem concerns people enjoying benefits improperly, not people paying different but possibly proper amounts for the same service. The third statement is correct because in this instance, the action of many free riders leads to a systemic shutdown. |
| 268 | Top | #74, 2nd line from bottom | Thus, choice(D) is the correct answer to this Except question. | (deleted) |
| 268 | Middle | #76, 2nd line | … this supports the first statement. | … this supports the second statement. |
| 268 | Middle | #76, last line | (insert text at end of explanation) | The first choice is wrong because the passage describes an “anechoic chamber” as filled with “sound-absorbing fiberglass wedges,” which are the opposite of the sound-reflecting objects required to propagate echoes. |
| 269 | Top | #81, 1st line | As the second paragraoh states… | As the second paragraph states… |
| 269 | Middle | #84, 1st and 2nd line | … the man of the house was at the warfront. | … the man of the house was at the war front. |
| 270 | Top | #86, 8th line | … believes that comfirmability is reasonable. | … believes that confirmability is reasonable. |
| 270 | Top | #86, 9th line | … the author statesin the last sentence… | … the author states in the last sentence… |
| 271 | Bottom | #97, 3rd line | This support… | This supports… |
| 281 | Middle | #157, 5th line | If Homer and Hesiod disagreed… | If Homer and Herodotus disagreed… |
| 281 | Bottom | #161, 3rd line from bottom | (insert text after “Thus, choice (D) is correct.”) | In choice (E), the phrase “they will promote the discrete quantal amounts of energy required” is unjustified, as it is the electrons that get promoted, not the discrete quantal amounts of energy required. The discrete quantal amounts of energy simply establish the wavelength range that the chromophores will absorb. |
| 294 | Top | #16 (C) | New apartment buildings would not be limited under the zoning plan. | Property taxes in the town are higher than in neighboring towns. |
| 294 | Top | #16 (D) | Under the new plan, developers may still erect apartment buildings. | Under the zoning plan, new apartment buildings would be exempt from the limits on new construction. |
| 335 | Bottom | #40, 3rd line from bottom | … equalt… | … equal… |
| 356 | Top | #5, 2nd line | … PEMDAS. | … PEMDAS. Thus, you get −8 ÷ 2 = –4. |
| 366 | Top | #6, (C)–(E) |
(Χ) -12 (Δ) -16 (Ε) -19 |
(C) -12 (D) -16 (E) -19 |
| 390 | Middle | #3, 3rd line of math | … or −(x − 4) = −16 ÷ 3. | … or −(x − 4) = 16 ÷ 3. |
| 399 | Top | #27, 4th line from top | 5 − 22 ≥ −2x | 5 − 22x ≥ −2x |
| 418 | Top | #55, 2nd line | … equalt… | … equal… |
| 455 | Bottom | #28, 1st line | Simpler explanation could avoid FOILing. Consider simplifying within parentheses, then multiplying out. | Multiply out Quantity A by FOILing: |
| 456 | Middle | #29, last line of math | –1,320 | 1,320 |
| 464 | Top | #4, 2nd line | … both pay the same percent of their respective incomes in tranportation fees. | … both pay the same positive percent of their respective incomes in transportation fees. |
| 474 | Top | #4, 2nd line | (insert text before “Quantity B is greater.”) | Therefore, half of Roselba’s fees will still be greater than Jane’s fees. |
| 493 | Bottom | #3, Quantity A | The number of distinct factors of 10 | The number of distinct positive factors of 10 |
| 495 | Top | #10, first line | … exactly four factors. | … exactly four positive factors. |
| 497 | Top | #20, first line | … how many factors? | … how many positive factors? |
| 505 | Middle | #19, 1st line | … then pg = 42… | … then pq = 42… |
| 525 | Top | #31/#30 | Question is numbered “31.” | Question should be numbered “30.” |
| 525 | Top | #31/#30 | Question is numbered “31.” | Question should be numbered “30.” |
| 531 | Middle | #14, Quantity A | The number of distinct factors of 32 | The number of distinct positive factors of 32 |
| 531 | Middle | #14, Quantity B | The number of distinct factors of 20 | The number of distinct positive factors of 20 |
| 555 | Bottom | #8, 2nd line from bottom | (34 + 4 + 2 minutes) | (35 + 4 + 2 minutes) |
| 556 | Bottom | #13, last line of math | [(100 – 25) ÷ (100 × 100)] = 75% | [(100 – 25) × 100] ÷ 100 = 75% |
| 557 | Top | #14, 2nd line from bottom | … avergae… | … average… |
| 568 | Top | #23, 2nd line | How many candies does Janie have? | How many candies does Anke have? |
| 615 | Bottom | #5, 2nd line from bottom | To eliminate of the… | To eliminate the… |
| 643 | Middle | #23, 3rd line from bottom |
Perimeter = 2 × 10 cm + 2 × 15 cm
Perimeter = 20 cm + 30 cm |
Perimeter = 2 × 15 cm + 2 × 10 cm
Perimeter = 30 cm + 20 cm |
| 654 | Top | #16, 2nd line | … the average of the 4 greatest numbers in this list is 20. | … the average of the 4 greatest numbers in this list is 17. |
| 654 | Middle | #16 (D) | 48 | 36 |
| 664 | Bottom | #16, last half of explanation | Various, to reflect changes to page 654 above. | The sum of the 4 greatest numbers is 68. The middle number is 16, the sum of the 3 smallest numbers is also 16, and the sum of the 3 greatest numbers is 52, so the difference is 36. |
| 665 | Middle | #18, 2nd line | Avgerage… | Average… |
| 689 | Top | #9, 8th line from top | … portion of the standard deviation. | … portion of the standard normal distribution. |
| 690 | Middle | #14, 9th line | Quantity A is asks for… | Quantity A is… |
| 695 | Middle | #31, 2nd line from bottom | … could measure exactly 3.0, or they could have a variety of different lengths that average to 3.0. | … could measure exactly 3.8, or they could have a variety of different lengths that average to 3.8. |
| 719 | Top | #34, 6th line | … = 1. | … = 15. |
| 728 | Middle | #3, 1st line | … Millbrook Middle School… | … Millbrook High School… |
| 728 | Bottom | #5, 2nd line | … Millbrook Middle School… | … Millbrook High School… |
| 735 | Top | #18, 1st line | … equal the to the sum… | … equal to the sum… |
| 752 | Top | Problem Set A comments | … Millbrook Middle School… | … Millbrook High School… |
| 840 | Top | #3, 4th line | y = −(4 ÷ 3)x – 1y | y = −(4 ÷ 3)x – 1 |
| 841 | Top | #5, 1st line at top | hit the x-axis above | hit the y-axis above |
| 843 | Bottom | #15, 6th line from bottom of page | … 1 can be plugged in for x and 4 plugged in for y… | … 1 can be plugged in for x and 3 plugged in for y… |
| 851 | Bottom | #1, diagram | (It is ambiguous, based on the question stem, which angle in triangle ABC is a right angle) | (Insert a small square inside angle A so that it is clear that angle A is the right angle) |
| 873 | Top | #19, 1st line | How many positive five-digit integers contain the digit grouping “57” (in that order) at least once? For instance 30,457 and 20,574 are two such integers to include, but 30,475 and 20,754 do not meet the restrictions. | How many times does the digit grouping “57” (in that order) appear in all of the five-digit positive integers? For instance, “57” appears once in 12,357, twice in 57,057, and does not appear in 24,675. |
| 873 | Middle | #19 (B) | 3,091 | 3,000 |
| 873 | Middle | #19 (C) | 3,500 | 3,471 |
| 873 | Middle | #19 (D) | 3,671 | 3,700 |
| 873 | Middle | #19 (E) | 4,000 (or 4,077) | 4,029 |
| 879 | Top | #1, 2nd line from bottom | … more clear… | … clearer… |
| 889 | Middle | #19, last 4 lines | … there are 1,000 + 900(3) = 3,700 such integers. This result double-counts, however, the cases with two 57’s in them: 5757X, 57X57, and X5757. The first two cases yield 10 numbers each, while the last case yields only 9 (because 05757 doesn’t count as a 5-digit number, by convention). Subtracting these 29 numbers, you get 3,671. |
… this adds up to 1,000 + 900(3) = 3,700 such integers. Note that this method will double count any integer that has two instances of the grouping “57” in it. For example, 57,357 will be counted both in the case of 57 _ _ _ and in the case of _ _ _ 57. In total, there are 10 ways a number could be counted both in the 57 _ _ _ and the _ _ _ 57 cases; there are 10 ways a number could be counted both in the 57 _ _ _ and the _ _ 57 _ cases; and there are 9 ways a number could be counted both in the _ 57 _ _ and _ _ _ 57 cases. This leaves 10 + 10 + 9 = 29 integers that are double-counted. However, it is fine that they are double-counted, because the question asks for the number of times the grouping “57” appears. These integers contain that grouping twice, so they should be counted twice, and the correct answer is 3,700. |
| 890 | Bottom | #23, last line | = (14 ÷ 72) ÷ (2 ÷ 72) | = (14 ÷ 72) + (2 ÷ 72) |
| 892 | Middle | #28, 6th line | … equalt… | … equal… |
| 896 | Middle | #34, last line | … equalt… | … equal… |
| 973 | Middle | #12, 1st line | Ameliorate, extenuate. | Ameliorate, mitigate. |
| 996 | Top | #18, 1st line | … American theater? | … theater? |
| 997 | Top | #2, 2nd line from bottom | … answer are… | … answers are… |
| 1018 | Middle | #16 (A) | 1,844 | 1,757 |
| 1018 | Middle | #16 (B) | 1,757 | 1,844 |
| 1034 | Middle | #20, all | (all instances of “by”) | (replace “by” with “on”) |
| 1048 | Top | 18th word, left column | adherants | adherents |