agha79 Wrote:GMAT prep exam one question. I was unable to find this in the forms. I searched using first few words of the question as a search.
Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length.
a) X^4 ≥ 1
b) X^3 ≤ 27
c) X^2 ≥ 16
d) 2 ≤ |x| ≤ 5
e) 2 ≤ 3x + 4 ≤ 6
OA: E
Let's think about what is means to have a solution set that when graphed on the number line is a single line segment of finite length. That means that I must have a specific set of solutions that begins in one spot and ends in another, encompasses everything in the middle, and does not create two lines.
I can rule some of these out pretty quickly. With A, I have possible values equal to or above 1 and equal to or below -1. This fails on two counts--two separate lines plus they go on to infinity. Same thing with C--4 and greater numbers work as do -4 and lesser numbers.
B is very similar--anything 3 or below will work, on through negative infinity.
D looks good at first, but we have two solutions because of the absolute value signs; either 2 to 5 or -2 to -5 will work. Two lines so we have to toss that out.
E is the only one left. You can solve by first obtaining the x for 2 ≤ 3x + 4 then obtaining the x for 3x + 4 ≤ 6; in other words, split the equation into two pieces.