by Ben Ku Sun Oct 25, 2009 3:39 am
One neat approach to factorial problems is to recognize something like this:
9 * 8! = 9!
So let's suppose you have something in 7! and you're trying to get 9!. You would multiply the first by 9*8.
9 * 8 * 7! = 9!
This will help us find a common denominator for the answer choices. From among the answer choices, you will find that 5(9!) is the greater common denominator. To change the answer choices to this denominator, you must:
(a) multiply numerator and denominator by 5*9, so the denominator is 5(9!)
(b) the denominator is already 5(9!)
(c) multiply numerator and denominator by 5, so the denominator is 5(9!)
(d) multiply numerator and denominator by 9*8, so the denominator is 5(9!)
(e) multiple numerator and denominator by 9, so the denominator is 5(9!)
If you perform the above, the answer choices become:
(a) 3/8! = 135 / 5(9)!
(b) 6(4!)/5(9!) = 144 / 5(9!)
(c) 4(3!)/9! = 120 / 5(9!)
(d) 3/5(7!) = 216 / 5(9!)
(e) 14/5(8!) = 126 / 5(9!)
Here, (D) is the largest fraction.
Ben Ku
Instructor
ManhattanGMAT