What is the value of x?
(1) x 2 – 5 x + 6 = 0
(2) x > 0
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
In the explanation for this D.S. question, the first quadratic is factored as:
(x-2)(x-3)=0
so x=2 or x=3
However, couldn't the equation also be factored as follows?:
(x-6)(x+1)
so x=6 x=-1
If you factor it this way, when you get the 2nd part that x>0, then you can answer C.
However, according to the CAT the answer is E as both the results of the first are positive.
Can you factor this question both ways listed above or did I make a mistake in the 2nd version?