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GMAT 5/18
 
 

What is the greatest prime factor of 4^17 - 2^28?

by GMAT 5/18 Sun May 13, 2007 12:23 am

Source: Gmat Prep, mba.com, Test II

Didn't know where to start on this one. Guessed incorrectly on the exam. :(

What is the greatest prime factor of 4^17 - 2^28?

a. 2
b. 3
c. 5
d. 7
e. 11

Thanks!
vanD
 
 

by vanD Sun May 13, 2007 2:47 pm

D

First reduce the exp till you have the same bases... 2^34-2^28=2^34(2^6-1)==> x(64-1)=x(63)==> x(3^2*7)

Hence 7..

hth
GMAT 5/18
 
 

by GMAT 5/18 Sun May 13, 2007 3:43 pm

vanD,

Thanks for helping out.

During the practise test I took, I managed to get to 2^34 - 2^28 (as you have shown).

However, I do not understand how you get to your next step of 2^34(2^6-1). Could you (or anyone else) please elaborate on this further?

Thanks a lot!
Guest
 
 

by Guest Sun May 13, 2007 6:02 pm

5/18, typo... it is 2^28 not 2^34.
I got this by common factoring 2^28 between 2^34 and 2^28 so 2^28(2^6-1) since 28+6=34
GMAT 5/18
 
 

by GMAT 5/18 Sun May 13, 2007 7:22 pm

Hey, thanks a lot man! That is a nice little move! :)

That kind of move is easy to see with basic algebra (e.g. 4x + 2x = 2x (2 + 1)), but harder for me to see using exponents. I will add it to my lookout list when using exponents. ;)
esledge
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by esledge Tue May 15, 2007 5:31 pm

Well done, everyone! A good hint that you should look for something to factor out is the tremendously large numbers involved in this problem. There is no way that you would be expected to actually compute 2^34 or 2^28. Thus, the expression must simplify by some more elegant means: factoring out the common term of 2^28.
Emily Sledge
Instructor
ManhattanGMAT
venkatsr
 
 

Exponent query

by venkatsr Sun Dec 28, 2008 1:10 pm

Hello,

Sorry to update an old thread. I tried this but getting a different answer.

2^34-2^28==>2^28(2^6-1)==> x(34-1)=x(33)==> x(3^1*11)

And I get (E) as the answer. Am I missing something here?


Regards, Sriram
venkatsr
 
 

by venkatsr Mon Jan 05, 2009 11:43 am

Please ignore the above. Realized my mistake.
RonPurewal
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by RonPurewal Fri Jan 09, 2009 6:54 am