Hi,
I'm quite confused as to the explanation of this problem in the study guide. To get the 160th term, they do 6+ (159x3)=483. Why do they multiply 3 by 159? Where is the 159 from? Please help.

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I know this DS problem from a CAT exam has been addressed in a previous thread. However, I do not understand the way that this problem is explained in the 'Solution' section of the CAT exam. Please help break the problem down into more understandable terms. Bob and Wendy planned to walk from their h...

Is the positive integer N a perfect square? (1) The number of distinct factors of N is even. (2) The sum of all distinct factors of N is even. The answer is D: EACH statement ALONE is sufficient. This is from one of the Manhattan CAT exams. I understand why the 1st statement is sufficient. However, ...

For instance, when I take the square root of an odd perfect square like 25, the two factors are 5 and 5. Thus, there is only 1 distinct factor, which is 5, and it is odd. When I take the square root of an even perfect square, like 16, it is 16=2x2x2x2. There is only 1 distinct factor and it is even....

The value of an investment increases by x% during January and decreases by y% during February. If the value of the investment is the same at the end of February as at the beginning of January, what is y in terms of x ? A) 200x/100 + 2x B) x(2 + x)/(1 + x)2 C) 2x/1 + 2x D) x(200 + x)/10,000 E) 100-(1...

S is a finite set of numbers. Does S contain more negative numbers than positive numbers? (1) The product of all the numbers in S is -1,200. (2) There are 6 numbers in S. OA is E I chose A because I believed that Statement 1 was sufficient to conclude that there were more negative numbers in set S s...

If (1/5)^m x (1/4)^18 = 1/(2x10^35), then m=? A) 17 B) 18 C) 34 D) 35 E) 36 OA is D I tried doing this problem several times in several different ways. I first attempted to split the 10 on the right side into its factors of 2 and 5. I also split the 4 on the rights into its factors of 2x2. However, ...

Thanks! I had tried searching it, but it wasn't coming up anywhere.

Since all the bases are the same, I merely added up all the exponents to equal 37, but that is the wrong answer. I also tried to factor out a 2^2 from each number, but I was lost as to which direction to go afterwards. 2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8= A) 2^9 B) 2^10 C) 2^16 D) 2^35 E) 2^37 OA is A. ...

thanks. that makes sense. the first approach just seems like it would take longer than 2 minutes.

Hi everyone, I am interested in taking a few refresher math courses (finance, accounting, statistics) prior to beginning my MBA program this Fall and was considering programs such as MBA Math (mbamath.com) and GMAT Business Ready (gmatbusinessready.com). I was wondering if anyone has any experience ...