How do we get possible values of 'x' when we have absolute values on both sides of the equation, as in: |x + 1| = 2|x - 1|? As a matter of background, I got this from the following question: Is |x| < 1 ? (1) |x + 1| = 2|x - 1| (2) |x - 3| > 0 Separately, (leaving aside shortcuts tailored to a ...

Treat it like any other absolute value statement. We know that if |x+a|<b then it can be "expanded" as: (x+a)<b and -(x+a)<b The same goes with the statement above: (x+1)=2(x-1) (equation 1) and -(x+1)=2(x-1) (equation 2) thanks for your response. Since the 'right hand side' of t...

thanks for your response. Since the 'right hand side' of the equation also has an absolute value sign, shouldnt we also examine two possible values i.e. for >0 and <0? I don't know what you mean by "shouldn't we also examine two possible values i.e. for >0 and <0"? We looked a...

This is from MGMAT CAT, Critical Reasoning: Adoption agency representative: It is true that eight of our last ten babies have been placed with parents who were personally acquainted with at least one of our staff members before initiating the adoption process. However, there is no truth to the accus...

If "B" is in fact correct, my reasoning would be as follows: It is true that eight of our last ten babies have been placed with parents who were personally acquainted with at least one of our staff members before initiating the adoption process. Indeed, all ten babies' new parents far sur...