guest612 Wrote:got it. totally get the explanation provided and how to solve this question as explained in the CAT.
However, can you please show me the error of my ways and tell me what is wrong with calculating the area of the hexagon using two trapezoids (resulting in the incorrect answer, D,) rather than six equalitaral triangles? This is more for future problems going forward so I don't actually make this error on the exam.
Thanks!
my mind-reading is a little bit off today, so, unfortunately, i can't tell you what's wrong with your solution unless you post it.
using two trapezoids should still give you the correct answer of 54√3 for the hexagon's area, though:
each trapezoid has height 3√3 (see my post above - this is almost certainly where you made your mistake)
each trapezoid has base1 = 6 and base2 = 12
so area of each trapezoid = (1/2)(3√3)(6 + 12) = 27√3
so hexagon = 2(27√3) = 54√3