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NMencia09
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Positive/Negative Inequality Algebra

by NMencia09 Mon Feb 27, 2012 6:52 pm

"Is m + z > 0?

"(1) m - 3z > 0
"(2) 4z - m > 0"

Question: I quickly realized neither (1) nor (2) are sufficient using theory, then when deciding between C and E, I ran into this question.

Combining inequalities: Is this approach correct:
1) add these two inequalities, leading to z>0
2) reason that if, as per statement (1), m-3z>0, and since z must be positive, that m must be positive too.
3) if both m and z are positive, m+z>0. (C) Sufficient together.

Is this a logical approach? i.e. to determine something that must be true according to the prompts, and then use that to deduce something about another variable in one of the prompts?

Hmm...?
abemartin87
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Re: Positive/Negative Inequality Algebra

by abemartin87 Mon Feb 27, 2012 11:51 pm

your logic is right dude m>3z>z>0
and yes if statment 1) is saying one thing like z>0 that carries over into the other statement
don't worry, be happy.

http://www.youtube.com/watch?v=yHFDa9efCQU
shubham_sagijain
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Re: Positive/Negative Inequality Algebra

by shubham_sagijain Tue Feb 28, 2012 1:29 am

yes, the logic and the approach is very much correct...
Another way to approach is :

S1 : It gives m > 3z
S2 : it gives m < 4z

So, from S 1 and S 2, we know 3z< m < 4z.

Now, the only way 4z can be greater than 3z is when z is positive.

Hence the answer is C :)

Thanks,
Shubh
NMencia09
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Re: Positive/Negative Inequality Algebra

by NMencia09 Wed Feb 29, 2012 1:14 pm

many thanks, Gentlemen!
RonPurewal
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Re: Positive/Negative Inequality Algebra

by RonPurewal Sat Mar 03, 2012 8:40 am

nice.

if you really get bored, you can also notice that ...
* multiplying statement 1 by 5
* multiplying statement 2 by 4
* adding the results
... actually gives m + z directly.
how 'bout that?
NMencia09
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Re: Positive/Negative Inequality Algebra

by NMencia09 Tue Mar 06, 2012 6:12 pm

You just blew my mind, dude.
nice.
RonPurewal
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Re: Positive/Negative Inequality Algebra

by RonPurewal Wed Mar 07, 2012 8:27 pm

here's another thread on this problem.
post41615.html#p41615