Pls help me in solving this question

[kittupriya.rv]

find the number of consecutive zeros at the end of 100!+200!. the given answer is 24 how is it possible?? 100! contains 24 zeros and 200! contains 49 zeros then hw cum the answer will be 24 pls explain in detail thanks in advance..

[atulgoel4u]

100! + 200! = 100! (1 + 200.199.198. .....101)

1 + 200.199.198 ....101 will have a 1 at the end

Now number of zeroes at the end of 100! is [100/5] + [100/25] = 20 + 4 = 24

Hence multiplication of 100! (1 + 200.199.198 ....101) will have 24 zeroes after 1.

[StaceyKoprince]

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