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anoo.anand
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Percentile problem

by anoo.anand Sun Oct 11, 2009 2:25 am

Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?
a. 72
b. 80
c. 81
d. 85
e. 92


Tried searching ...has not yet been solved.. :)

I solved it doiing:

number of students less then angela = 71 ..in class 1

no of students less then angela = 80-19 = 61 -60 = 60 below her in class 2

thus : 71 + 60 = 131

( x/100)*160 = 131

=> x = (131 * 100 ) / 160 = 81 .87 .. = 81

but the answer is not 81 . :)
acethegmat
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Re: Percentile problem

by acethegmat Fri Oct 23, 2009 4:07 pm

Angela’s grade was in the 90th percentile out of 80 grades in her class. In another class of 100 students there were 19 grades higher than Angela’s. If nobody had Angela’s grade, then Angela was what percentile of the two classes combined?

Your question stem missed out some key words. You should be able to solve it now:

90th percentile means 8 of 80 students
19 of 100 students - given

hence 19+8 = 27 students

27/180 - 15%
1 - 15% = 85%

Is 85 % the answer..?
RonPurewal
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Re: Percentile problem

by RonPurewal Sat Oct 24, 2009 8:31 am

post4998.html#p4998

so is it angela, or amy?
nitin_prakash_khanna
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Re: Percentile problem

by nitin_prakash_khanna Sat Oct 24, 2009 10:57 am

It looks like Amy got those grades in 2007 and Angela got the same in 2009 :>
Ben Ku
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Re: Percentile problem

by Ben Ku Thu Oct 29, 2009 1:18 am

Haha. Nice.
Ben Ku
Instructor
ManhattanGMAT
gal.afgon
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Re: Percentile problem

by gal.afgon Fri Sep 06, 2013 3:39 am

I'm always surprise to notice that Gmat can be so hilarious . Usually when Ron is making fun on small and tiny things.

It's funny to read your posts.

Thanks.
jnelson0612
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Re: Percentile problem

by jnelson0612 Sun Sep 08, 2013 2:15 pm

:-)
Jamie Nelson
ManhattanGMAT Instructor