edadams1 Wrote:Hi,
I also had trouble with this DS problem. Unfortunately the explanations that were provided still are not very clear to me. Would someone be willing to try and solve this problem from start to finish so I can see the entire thought process straight through?
Thanks
Sure. Let's look at the problem again:
"If x >1, what is the value of integer x?
1. There are x unique factors of x
2. The sum of x and any prime number larger than x is odd."
Okay, so we know that x is an integer that is 2 or greater. What is x?
Let's start with statement 2: x + a prime number larger than x is odd. I would think, hmm, almost all prime numbers are odd themselves. Let me make a list of prime numbers: 2, 3, 5, 7, 11, 13, etc. Let's come up with some values:
x could be 2. Any prime number larger than 2 is odd, so 2 +odd = odd. 2 works as a value of x.
x could be 4. An prime number larger than 4 is odd, so 4 + odd = odd. 4 works as a value of x.
Statement 2 does not tell me what x is; x could be 2 or 4, or really any even number that is 2 or greater. Cross off BD.
Let's go to statement 1: 1. There are x unique factors of x.
Let's test some values:
2--There ARE 2 unique factors of 2, 1 and 2. This works.
3--There ARE NOT 3 unique factors of 3. There are only two, 1 and 3. This doesn't work.
4--There ARE NOT 4 unique factors of 4. There are three, 1, 2, and 4.
5--There ARE NOT 5 unique factors of 5.
6--There ARE NOT 6 unique factors of 6.
See where this is heading? 1 and 2 are the only numbers that have the same number of factors as the number itself. We know that x is greater than 1, so x must be 2. The answer is A.