Q: (n - 2)^-1 (2 + n)
If n >2 and (2/n) is substituted for all instances of n in the above expression, then the new expression will be equivalent to which of the following:
Answer Choices:
A. (n + 1)(n - 1)^-1
B. -(n + 1)(n - 1)^-1
C. -(n - 1)(n + 1)^-1
D. (2 + n)^-1(n - 2)
E. (n - 2)^-1(2 + n)
Answer B
MGMAT states to pick a number to solve this equation. I picked n=4, however after solving the equation, i get a target answer of (-5/3). Whereas, MGMAT picked n=3, and got a target answer of (-2).
How would one know to pick n=3 instead of n=4? Why is that n=4 doesn't give me the same target answer as n=3?
Below is how i solved n=4
Q: (n - 2)^-1 (2 + n); substitute (2/n) for n, n >2
n=4; even though 2/4 = 1/2, i decided to avoid rounding here
(2/4 -2)^-1 (2+2/4)
(-6/4)^-1(10/4)
(-4/6)(10/4)
(-10/6) = (-5/3)
Explanation provided by MGMAT
This problem is an algebra problem that features VICs, so we can attack it multiple ways. Although we could use Direct Algebra, the complexity of the substitution combined with the negative exponents provides a hint that using Direct Algebra might take more than two minutes. Instead, we can Pick Numbers and Calculate a Target because we can then plug our choice for n directly into the answer choices and quickly evaluate all of them in less than 2 minutes.
We should start by picking 3 for n because 3 is the smallest integer that fits the constraint of n > 2. Let n = 3. Replace n with (i.e., 2/3) in the expression given in the question to compute the target number.