Math Question

[nk2120]

Solve:
[(1001)^2-(999)^2] / [(101)^2-(99)^2]=?

Answer: 10

I can't figure out how to simplify this...would appreciate anybody's help, thanks!

[nk2120]

nevermind, figured it out. in case anybody's interested:

((1001+999)(1001-999))/((101+99)(101-99))= (2000*2)/(200*2)= 10

[RonPurewal]

this is another problem that has been posted several times.

sampler:

http://www.manhattangmat.com/forums/gma ... t2760.html

http://www.manhattangmat.com/forums/100 ... t4996.html

http://www.manhattangmat.com/forums/post8978.html

search terms: 999 1001