by Nov1907 Thu Nov 15, 2007 1:55 am
Aaah. Just got this question on my second Gprep and clicked C as the answer and realised after the test that the solutions can only be integers and so B was sufficient. Let me explain.
Let the number of 23 cent pencils be x. Let the number of 21 cent pencils be y. (1) states that x+y=6. That is clearly insufficient. Let us consider (2): 23x+ 21y = 130. Now x and y are integers greater than 0.
23x = 130-21y. So the RHS needs to be greater than zero and a multiple of 23. Since 130-21y >=23 we have y<=(107/21) y<= 5.abc. So only possible values for y according to this inequality 1,2,3,4,5. Now x also needs to be an integer. So for x to be an integer only solution is y = 4. In this case x = 2 (In fact the first statement gives you a hint of what to look for because it says x+y = 6.). Hence Sufficient - B is the answer. This is the best solution I could think of.If there is something more intuitive I would like to know. Thanks!