In triangle ABC angle A is the greatest angle. D is the foot of the
perpendicular dropped on to BC from A. Is triangle ABC
right-angled?
A) AD^2 = BDxDC
B) AD/DC < BD/AD
My answer is E) as it will make these sub-traingles similar to make triangle isosceles but we can have still have 90-45-45 or 120-30-30 combination.
Both conditions are self contradictory so C cant be choice.