Is (m + z) > 0?

[Harish Dorai]

Is (m + z) > 0?

1) m - 3z > 0

2) 4z - m > 0

[Guest]

Posted: Fri Aug 10, 2007 2:40 pm


Is (m + z) > 0?

1) m - 3z > 0

2) 4z - m > 0

1 tells m > 3z , not suffecient
2 tells z > m/4 not sufficient.

Add both the ineq's (Add is fine). Gives z > 0
since m > 3z, z>0 so m>0

Hence m+z > 0

Answer is C.

[anadi]

that you can add the inequalities if they have same sign, either both > or both <.

[Harish Dorai]

wonderful explanation. (C) is the correct answer.

[ali_sha12j]

Posted: Fri Aug 10, 2007 2:40 pm


Is (m + z) > 0?

1) m - 3z > 0

2) 4z - m > 0

1 tells m > 3z , not suffecient
2 tells z > m/4 not sufficient.

Add both the ineq's (Add is fine). Gives z > 0
since m > 3z, z>0 so m>0

Hence m+z > 0

Answer is C.

how come adding the two inequalites gave z>0. i have a hard time understanding inequalites and their operations

[RonPurewal]

how come adding the two inequalites gave z>0. i have a hard time understanding inequalites and their operations

if you have 2 inequalities that face the same way (i.e., either both ">" or both "<"), then you can
* add the left sides
* add the right sides
* keep the same "<" or ">"

if you don't understand these sorts of things about how inequalities work, then you should check out the inequalities section in our Equations/Inequalities/VIC strategy guide.

[suchit.pandey]

wrong post..srry

[tim]

okay..